(x+3)(x^2+2x+4+x)=

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Solution for (x+3)(x^2+2x+4+x)= equation: 


Simplifying
(x + 3)(x2 + 2x + 4 + x) = 0

Reorder the terms:
(3 + x)(x2 + 2x + 4 + x) = 0

Reorder the terms:
(3 + x)(4 + 2x + x + x2) = 0

Combine like terms: 2x + x = 3x
(3 + x)(4 + 3x + x2) = 0

Multiply (3 + x) * (4 + 3x + x2)
(3(4 + 3x + x2) + x(4 + 3x + x2)) = 0
((4 * 3 + 3x * 3 + x2 * 3) + x(4 + 3x + x2)) = 0
((12 + 9x + 3x2) + x(4 + 3x + x2)) = 0
(12 + 9x + 3x2 + (4 * x + 3x * x + x2 * x)) = 0
(12 + 9x + 3x2 + (4x + 3x2 + x3)) = 0

Reorder the terms:
(12 + 9x + 4x + 3x2 + 3x2 + x3) = 0

Combine like terms: 9x + 4x = 13x
(12 + 13x + 3x2 + 3x2 + x3) = 0

Combine like terms: 3x2 + 3x2 = 6x2
(12 + 13x + 6x2 + x3) = 0

Solving
12 + 13x + 6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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